Question
Time is taken by two trains running in opposite
directions to cross a man standing on the platform in 26 seconds and 16 seconds respectively. It took 18 seconds for the trains to cross each other. What is the ratio of their speeds?Solution
Let the speed one train be x m/s and the speed of the second train be y m/s. Length of the first train = Speed × Time = 26x Length of second train = Speed × Time = 16y So, {(26x + 16y)/(x+y)} = 18 ⇒  26x + 16y = 18x + 18y ⇒ 8x = 2y Therefore, x:y = 1:4
I. 3x2 = 2x2 + 9x – 20
II. 3y2 = 75
I. x2 – 36 = 0
II. y2 - 7y + 6 = 0
I. 4p² + 17p + 15 = 0
II. 3q² + 19q + 28 = 0
I: √(100 x4 + 125x4) + 7x + 41/2 = -4x
II: 3√(64y3) x 2y + 19y + 72 = -3y +...
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 21x + 110 = 0
Equation 2: y² - 23y + 132 = 0
I. 3x² - 22 x + 40 = 0 Â
II. 4y² + 22y + 24 = 0  Â
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 13x² - 60x + 47 = 0
Equation 2: 17y² - 80y + 63 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 42x + 392 = 0
Equation 2: y² - 46y + 480 = 0
I. 2b2 - 37b + 143 = 0
II. 2a2 + 15a - 143 = 0
(i) 2x² – 9x + 10 = 0
(ii) 4y² – 12y + 9 = 0
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