Question

    Two boys are on opposite sides of a tower of 100 m height. If they measure the elevation of the top of the tower as 30° and 45° respectively then the distance between the boys is?

    A 100√3m Correct Answer Incorrect Answer
    B 100 (√3 + 1)m Correct Answer Incorrect Answer
    C (100√3 - 1)m Correct Answer Incorrect Answer
    D (100√3 + 1)m Correct Answer Incorrect Answer

    Solution

    Let AB is tower of 100m height x,y are the place where 2 boys standing. ∠AxB = 30° ∠AyB = 45° D = h (cotα + cotβ) D = 100 (cot30° + cot45°) D = 100 (√3 + 1) Then distance between the boys is = 100 (√3 + 1)

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