Let the Initial quantity of Mixture be 12x Total mixture after 12 litre of mixture drawn off = (12x-12) According to question, Quantity of Milk = (12x-12) × 7/12 Quantity of Water = (12x-12) × 5/12 After adding 8 litre water, Quantity of water in Mixture = (12x-12) × 5/12 + 8 Ratio of Milk and water after replacing = 1 : 1 ((12x-12)× 7/12)/((12x-12)× 5/12+ 8) = 1/1 (12x-12) × 7/12 = (12x-12) × 5/12 + 8 (84x-84)/12 = (60x-60)/12 + 8 84x-84=60x-60+96 x=5 So total Mixture = 12x = 12 × 5 = 60 litre Total milk in Initial Mixture = 60/12 × 7 = 35 litre
11.89 × 2.10 × 4.98 × 4.03 ÷ 7.98 of 15.03 = ?
9.8 × 77.9 ÷ (2.3)2= ?
26.23 × 31.82 + 44.8% of 1200 + ? = 1520
15.1 + 3.97 – 9.07 × 1.96 = √?
? = 49.99² ÷ (1.98⁵ + 8.01 × 89.91) + 75.15% of (263.89 × 49.11)
480.11 ÷ 15.98 × 5.14 – 134.9 = √?
(?)2 + 3.113 = 22.92 – 61.03
20.11% of 119.99 + √80.97 ÷ 3.02 = ?
(256.19 ÷ 63.99) 2.05 X (7.99) = 2 ? + 2.05
15.05% of 1599.88 + 29.99 × 12.01 - 420.05 = ?