Let the speed one train be x m/s and the speed of the second train be y m/s. Length of the first train = Speed × Time = 30x Length of second train = Speed × Time = 22y So, {(30x + 22y)/(x+y)} = 25 ⇒ 30x + 22y = 25x + 25y ⇒ 5x = 3y Therefore, x:y = 3:5
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