Question
Time is taken by two trains running in opposite
directions to cross a man standing on the platform in 31 seconds and 19 seconds respectively. It took 24 seconds for the trains to cross each other. What is the ratio of their speeds?Solution
Let the speed one train be x m/s and the speed of the second train be y m/s. Length of the first train = Speed × Time = 31x Length of second train = Speed × Time = 19y So, {(31x + 19y)/(x+y)} = 24 ⇒  31x + 19y = 24x + 24y ⇒ 7x = 5y Therefore, x:y = 5:7
The value of the expression (1 + sec22° + cot68°)(1 – cosec22° + tan68°) is
If x + y + z = 19, xyz = 216 and xy + yz + 2x = 114, then the value of √ x3 + y3 + z3 + xyz is :
Solve the equation:
3(x − 2) + 4(2x + 1) = 5(2x − 3) + 7
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Quanti...
 is equal to:
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