Question
X started to run from point βAβ to βBβ at a
speed of 28 km/hr at 9:00 am and Y started to run from point βBβ to βAβ at a speed of 12 km/hr at 11:00 am. If they meet each other at 3:00 pm then find the distance between points βAβ and βBβ.Solution
Distance covered by X in 2 hours = 28 Γ 2 = 56 km Relative speed of X and Y = 28 + 12 = 40 km/hr Sum of distance covered by both in 4 hours = 40 Γ 4 = 160 km Total distance between points βAβ and βBβ = 56 + 160 = 216 km
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