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Let the distance covered by ‘A’ in the time ‘B’ covers 220 metres be ‘x’ metres (x/220) = (6/11) Or, x = 120 So, m = 220– 120 = 100 metres
15.98% of 399.76 × 2.98 = ?% of 599.93
(660.05) ÷ 120.04% of (55.022/2.24) = (? ÷ 10.02)
126.003 × 11.987 + 23.04 × 12.96 = ?
49.96% of 861.34 + 2250% of 55.12 = ?
? = 340.24 + 1001.97 – 6.992
180.25 × 14.995 ÷ √26 = ? × 5.985
(?)2 + 5.113 = 26.92 – 28.03
619.97 ÷ 20.01 X 124.99 ÷ 24.91 = ?
? = 685.24 + 1024.97 – 9.992