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ATQ, Relative speed = 36 + 64 = 100 km/h Relative speed increases by 2 km/h (6 – 4 = 2) every hour Let they meet after ‘t’ hours, Relative speed in 1st hour = 100 km/h Relative speed in 2nd hour = 102 km/h So, relative speed will be as 100 km/h, 102 km/h, 104 km/h, 106 km/h, 108 km/h ........ Distance travelled in 4 hours = 100 + 102 + 104 + 106 = 412 km Distance remaining = 493 – 412 = 81 km Relative speed in 5th hour = 108 km/h Hence, desired time = 4 + 81/108 = 4.75 hours = 4 hours 45 minutes
? = 44.78% of 839.91 – 48.12% of 774.89 + 55.77% of 1024.85
? 3 + 95.06 X 39.87 ÷ 5.03 = 1271.89
10.10% of 999.99 + 14.14 × 21.21 - 250.25 = ?
(155.34 + 234.78) ÷ 12.65 = ? ÷ 4.99
(124.901) × (11.93) + 219.95 = ? + 114.891 × 13.90
74.91% of 639.95 – 599.98% of 45 + 119.987 = ?
`(sqrt(960.87)xx9.932+sqrt(629.998)xx26.385)/(sqrt(1028.902)xx4.977)=?`
`sqrt623.798` × 24.034 +`sqrt403.898` × 17.907 =?
P spends 20% of his monthly income in travelling. He spends 25% of his monthly income on household expenses and spends 15% of his monthly income on fami...