Question
Ajay and Bharti are initially 493 km apart. They start
jogging towards each other with speeds of 36 km/h and 64 km/h, respectively, at the same time. If Ajay increases his speed by 6 km/h every hour and Bharti decreases her speed by 4 km/h every hour, find the time it takes for them to meet.Solution
ATQ, Relative speed = 36 + 64 = 100 km/h Relative speed increases by 2 km/h (6 – 4 = 2) every hour Let they meet after ‘t’ hours, Relative speed in 1st hour = 100 km/h Relative speed in 2nd hour = 102 km/h So, relative speed will be as 100 km/h, 102 km/h, 104 km/h, 106 km/h, 108 km/h ........ Distance travelled in 4 hours = 100 + 102 + 104 + 106 = 412 km Distance remaining = 493 – 412 = 81 km Relative speed in 5th hour = 108 km/h Hence, desired time = 4 + 81/108 = 4.75 hours = 4 hours 45 minutes
(752.09 - 43.04 x 7.94) ÷  16.9 = ?
56.02% of 1499.98 + 64.04% of 2501.01 = ? + 25.05 × 49.98 + 6.063
What approximate value should come in the place of (?) in the following questions?
908.90 –190.32 + √? = 23.03 * 5.2 + 24.72
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(17.17 ×  21.98) + 34.15% of 649.99 = ? + 125.34
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
37.5% of [34.99 ÷ (21.07/5.98) of 7.99 ÷ 2.18] = ?
2387.56 + ? – 2248.14 = 1765.45 – 1574.23
What approximate value will come in place of the question mark (?) in the following question?
29.98% of 549.99 = ? - 254.97 + 79.98% of 74.99Â
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