Question
Train βAβ running with a speed of 54 km/hr. can
cross a standing goods train of 4 times its length in 20 seconds. Find the time taken by 240 meters long train βBβ which is coming from the opposite direction of train βAβ, with a speed of 9 m/s, to cross-train βAβ.Solution
Let the length of train βAβ be βxβ meters. Therefore, the length of the goods train = β4xβ meters Speed of train βAβ = 54 Γ (5/18) = 15 m/s According to the question, 4x + x = 15 Γ 20 => 5x = 300 => x = 60 Therefore, the time is taken by train βBβ to cross train βAβ = {(60 + 240)/ (15 + 9)} Β = 300/24=50/4=12.5second
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