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Start learning 50% faster. Sign in nowSuppose the distance is x km and Speed of the train is y km/hr Thus, we have two relations: x/y = 90/60 x = 3/2 y …………(i) x/(y-10) = 96/60 x/(y-10) = 8/5 ………….(ii) From (i) and (ii), 3/2 y = 8/5 (y – 10) 3/2 y - 8/5 y = - 16 (15y - 16y)/10 = - 16 (-y)/10= -16 y = 160 Therefore, speed = 160 km/hr and Distance, x = 3/2 y = 3/2× 160 = 240 km
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