Question
A train covers a distance between stations Dehradun to
Rudrapur in 90minutes. If the speed is reduced by 10 km/hr, it will cover the same distance in 96 minutes. What is the distance between the two stations (in km)? Also find the speed of train?Solution
Suppose the distance is x km and Speed of the train is y km/hr Thus, we have two relations: x/y = 90/60 x = 3/2 y …………(i) x/(y-10) = 96/60 x/(y-10) = 8/5 ………….(ii) From (i) and (ii), 3/2 y = 8/5 (y – 10) 3/2 y - 8/5 y = - 16 (15y - 16y)/10 = - 16 (-y)/10= -16 y = 160 Therefore, speed = 160 km/hr and Distance, x = 3/2 y = 3/2× 160 = 240 km
More Time and distance Questions
√ [? x 11 + (√ 1296)] = 16
? = 6.25% of 240 + 252 + 172 – 16 × 17
436 × 794 – 68210 =? + 85730
?/4 ÷ 9/? = 15% of 800 + `1(2/3)` × `1(1/5)` × 1/2
16 × 14 + 30 × 21 = 14 × ?
60% of 250 + 14 × 10 - 210 = ?
What will come in the place of question mark (?) in the given expression?
30% of 520 + 16% of 1500 = ? + 244
33 × 5 - ?% of 250 = 62 - 6
140% of 9/8 of ? = 108% of 2800
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