Question
If a car runs at 50 km/hr, it reaches its destination
late by 14 minutes but if runs at 60 km/hr it is late by 9 minutes. What is the correct time for the journey? MTSolution
Distance = Difference in time x (S1 x S2)/(S1 – S2) D = [14 – 9]/60 x {(50 x 60)/[60 – 50]} => (5/60) x (60 x 50)/10 => 25 km Time, T = D/S (take any one of the speed) => 25/50 = 25/50 x 60 = 30 minutes Then, correct time is 30 – 14 = 16 minutes
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