Distance = Difference in time x (S1 x S2)/(S1 – S2) D = [14 – 9]/60 x {(50 x 60)/[60 – 50]} => (5/60) x (60 x 50)/10 => 25 km Time, T = D/S (take any one of the speed) => 25/50 = 25/50 x 60 = 30 minutes Then, correct time is 30 – 14 = 16 minutes
I. 7x² + 52x + 21 = 0
II. 6y² + 7y - 24 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 54x + 704 = 0
Equation 2: y² - 44y + 448 = 0
One of the roots of the equation p2 - (y+3)p + 6y = 0 is cube of 2. What will be the difference of other root and 'y'.
I. 2y² - 11 y + 15 = 0
II. 2x² + 3x – 14 = 0
I. 63x2+ 148x + 77 = 0
II. 21y2+ 89y + 88 = 0
I. 49y2+ 35y + 6 = 0
II. 12x2+ 17 x + 6 = 0
I. 8x² + 2x – 3 = 0
II. 6y² + 11y + 4 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 24x + 143 = 0
Equation 2: y² - 26y + 165 = 0
I. y/16 = 4/y
II. x3= (2 ÷ 50) × (2500 ÷ 50) × 42× (192 ÷ 12)
I. 104x² + 9x - 35 = 0
II. 72y² - 85y + 25 = 0
