Question
Three numbers ‘A’, ‘B’ and ‘C’ are such that ‘A’ is one-fifth of ‘B’ and ‘C’ is equal to the average of ‘A’ and ‘B’. If the sum of these three numbers is 720, then find the sum of ‘A’ and ‘C’.
Solution
Let the value of ‘B’ be ‘10x’ So, value of ‘A’ = 10x/5 = ‘2x’ So, value of ‘C’ = (10x + 2x)/2 = 12x/2 = ‘6x’ ATQ; 2x + 10x + 6x = 720 Or, 18x = 720 Or, x = 40 So, the sum of ‘A’ and ‘C’ = 2x + 6x = 8x = 8 × 40 = 320
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