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    Question

    Three numbers β€˜A’, β€˜B’ and β€˜C’ are such that

    β€˜A’ is one-fifth of β€˜B’ and β€˜C’ is equal to the average of β€˜A’ and β€˜B’. If the sum of these three numbers is 720, then find the sum of β€˜A’ and β€˜C’.
    A 180 Correct Answer Incorrect Answer
    B 240 Correct Answer Incorrect Answer
    C 320 Correct Answer Incorrect Answer
    D 400 Correct Answer Incorrect Answer

    Solution

    Let the value of β€˜B’ be β€˜10x’ So, value of β€˜A’ = 10x/5 = β€˜2x’ So, value of β€˜C’ = (10x + 2x)/2 = 12x/2 = β€˜6x’ ATQ; 2x + 10x + 6x = 720 Or, 18x = 720 Or, x = 40 So, the sum of β€˜A’ and β€˜C’ = 2x + 6x = 8x = 8 Γ— 40 = 320

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