Question
In the question, two equations I and II are given. You
have to solve both the equations to establish the correct relation between x and y and choose the correct option. I. 20x² – 43x + 21 = 0 II. 5y² – 17y + 14 = 0Solution
ATQ,
From I:
20x² – 43x + 21 = 0
20x² – 15x – 28x + 21 = 0
5x(4x – 3) – 7(4x – 3) = 0
(5x – 7)(4x – 3) = 0
x = 7/5, 3/4
x = 1.4, 0.75
From II:
5y² – 17y + 14 = 0
5y² – 10y – 7y + 14 = 0
5y(y – 2) – 7(y – 2) = 0
(5y – 7)(y – 2) = 0
y = 7/5, 2.
Y = 1.4, 2
So x ≤ y
17 32 99 ? 1965 11784
...77 ? 190 257 331 412
...Given below are three numbers series I, II and II where each series contains a wrong (odd one out) term. The wrong number in series I, II and III are '...
91   93   97   100   ?   113
12 Â Â Â 11 Â Â Â Â 21 Â Â Â Â 62 Â Â Â Â ? Â Â Â Â Â 1234
13 15 ? 63 143 293
...102     153      306      765       ?     8032.5
...17 ? 33 44 57 72
...3 5 7 25 85 481
...1 4 13 46 ? 976
...
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