Question
Train ‘L’ is travelling with a speed of 90 km/hr
and crosses a vertical pole in 4 seconds. Train ‘K’ is 60 metres longer than ‘L’ and travelling with a speed 1/5th less than that of train 'L'. In how much time train K can cross a 180 metres long platform?Solution
Speed of train ‘L’ = 90 × (5/18) = 25 m/sec Length of train ‘L’ = 25 × 4 = 100 metres Therefore, speed of train ‘K’ = (4/5) × 25 = 20 m/sec Length of train ‘K’ = 100 + 60 = 160 metres Required time taken = (160 + 180)/20 = 340/20 = 17 seconds
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