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    Question

    Train ‘L’ is travelling with a speed of 90 km/hr

    and crosses a vertical pole in 4 seconds. Train ‘K’ is 60 metres longer than ‘L’ and travelling with a speed 1/5th less than that of train 'L'. In how much time train K can cross a 180 metres long platform?
    A 20 sec Correct Answer Incorrect Answer
    B 18 sec Correct Answer Incorrect Answer
    C 19 sec Correct Answer Incorrect Answer
    D 17 sec Correct Answer Incorrect Answer

    Solution

    Speed of train ‘L’ = 90 × (5/18) = 25 m/sec Length of train ‘L’ = 25 × 4 = 100 metres Therefore, speed of train ‘K’ = (4/5) × 25 = 20 m/sec Length of train ‘K’ = 100 + 60 = 160 metres Required time taken = (160 + 180)/20 = 340/20 = 17 seconds

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