Question
Train A and B can cross a 350 meters long platform in
the same time. The length of Train A is 250 meters and the speed of Train B is 3/2 times the speed of Train A. If Train A crosses a bridge of the same length as of Train B in 50 seconds, then find the time (in seconds) taken by Train B to cross a tunnel 230 m long.Solution
Let speed of train A = 2x meters/second
And speed of train B = 3x meters/second
Let length of train B = y meters ATQ, (y + 350)/3x = (250 + 350)/2x
y + 350 = 900
y = 550 meters Speed of train A = (250 + 550)/50 = 16 m/sec
Speed of train B = 3/2 × 16 = 24 m/sec Required time = (550 + 230)/24 = 26 sec
Solve |2x–5| = |x+1|.
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