Question
I. 2y2Β β 19y + 35 = 0 II.
4x2Β β 16x + 15 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.Solution
I. 2y2 β 19y + 35 = 0Β 2y2 β 5yΒ β 14 y + 35 = 0 y (2 y β 5) β 7(2 y β 5) = 0 (2 y β 5)(y β 7) = 0 y = 7, 5/2 II. 4x2Β β 16x + 15 = 0 4x2Β β 6xΒ β 10 x + 15 = 0 2 x(2 x β 3) β 5(2 x β 3) = 0 (2 x β 3)(2x β 5 )=0 x = 5/2, 3/2 Hence, x β€y
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