Question
I.8(x+3) +Â 8(-x) =72Â
II. 5(y + 5) + 5(-y) = 150 In the following questions, two equations numbered I and II are given. You have to solve both the equations and find out the correct option. Give answerÂSolution
I. 8(x+3) + 8(-x) =72 8x × 83 + (1/8)x - 72 = 0 Let 8x = a 512a + 1/a - 72 = 0 512a² + a - 72a = 0 512a² - 72a + 1 = 0 512a² - 64a - 8a + 1 = 0 64a (8a-1) -1(8a-1) = 0 (64a-1) (8a-1) = 0 a = 1/8, 1/64 8x = 1/8 x = -1  8x = 1/64 x = -2  II. 5(y + 5) + 5(-y) = 150 55 × 5y + (1/5)y - 150 = 0 Let 5y = b 3125b + 1/b - 150 = 0 3125b² - 150b + 1 = 0 3125b² - 125b - 25b + 1 = 0 125b(25b-1) -1(25b-1) = 0 b = 25, 125 5y = 1/25 y = -2 5y = 1/125 y = -3 Hence, x ≥ yÂ
(i) 2x² – 12x + 16 = 0
(ii) 2y² – 20y + 48 = 0
I. x2 – 13x + 36 = 0
II. 3y2 – 29y + 18 = 0
Solve: 3x² − 7x − 6 = 0
I. 5x + 2y = 31
II. 3x + 7y = 36
What is the average salary of 10 officers , if a clerk’s salary is Rs. 15,000?
Statement I: The total salary of 10 officers and 5 clerk is Rs....
For what values of k does the equation x² – (k+1)x + k = 0 have two distinct real roots, both greater than 1?
I. x2 + x – 42 = 0
II. y2 + 6y – 27 = 0
I. 25p + 2(2p2 – 1) = 8(p + 5)
II. 8q2 + 35q – 78 = 0
I. x2 + 24x + 143 = 0
II. y2 + 12y + 35 = 0
I. 2x² - 12x + 16 = 0  Â
II. 4y² - 8y - 12 = 0  Â