Question
(i) 2xΒ² β 9x + 10 = 0 (ii) 4yΒ² β 12y + 9 =
0 In each of these questions, two equations (i) and (ii) are given. You have to solve both the equations and give answers:Solution
(i) 2xΒ² β 9x + 10 = 0 =>2xΒ² β 5x β 4x + 10 = 0 =>x (2x β 5) β2 (2x β 5) = 0 => (x β 2) (2x β 5) = 0 => x = 2, 2.5 (ii) 4yΒ² β 12y + 9 = 0 => 4yΒ² β 6y β 6y + 9 = 0 => 2y (2y β 3) β3(2y β 3) =0 => (2y β 3) (2y β 3) = 0 => y = 3/2, 3/2 Hence, x > y.
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