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    Question

    I. 18x² + 27x + 10 = 0 II. 12y² + 17y +

    6 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.
    A if x>y Correct Answer Incorrect Answer
    B if x≥y Correct Answer Incorrect Answer
    C if x Correct Answer Incorrect Answer
    D if x ≤y Correct Answer Incorrect Answer
    E if x=y or the relationship cannot be established Correct Answer Incorrect Answer

    Solution

    I. 18x² + 27x + 10 = 0 18x² + 12x + 15 x + 10 = 0 6 x(3 x + 2) + 5(3 x + 2) = 0 (6 x + 5) (3 x + 2) = 0 ∴ x = -5/6, -2/3 II. 12y² + 17y + 6 = 0 12y² + 9y + 8y + 6 = 0 3y (4 y + 3) + 2(4 y + 3) = 0 (3 y + 2) (4 y + 3) = 0 ∴ y = -2/3, -3/4 Hence, relationship cannot be established between x and y

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