📢 Too many exams? Don’t know which one suits you best? Book Your Free Expert 👉 call Now!
  • google app store apple app store
    • âś–

      Question

      I. 2p2 - 3p – 2 = 0 II. 2q2

      - 11q + 15 = 0 In each question two equations are provided. On the basis of these you have to find out the relation between p and q. Give answer.
      A if p = q Correct Answer Incorrect Answer
      B if p > q Correct Answer Incorrect Answer
      C if q > p Correct Answer Incorrect Answer
      D if p ≥ q Correct Answer Incorrect Answer
      E if q ≥ p Correct Answer Incorrect Answer

      Solution

      I. 2p2 - 3p – 2 = 0,
      (2p + 1)( p - 2) = 0
      p = - (1/2) or 2,
      II. 2q2 - 11q + 15 = 0
      (2q - 5) (q - 3) = 0,
      q = (5/2) or 3;
      Hence, q > p.
      Alternate Method:
      if signs of quadratic equation is -ve and -ve respectively then the roots of equation will be -ve and +ve. (note: -ve sign will come in smaller root)
      So, roots of first equation = p = -1/2, 2
      if signs of quadratic equation is -ve and +ve respectively then the roots of equation will be +ve and +ve.
      So, roots of second equation = q = 5/2, 3
      After comparing roots of quadratic eqution we can conclude that q > p.

      Practice Next
      More Quadratic equation Questions

      Relevant for Exams:

      ask-question