Question
I. 6x² - 23x + 7 = 0 II. 6y² - 29y + 9
= 0Solution
I. 6x² - 23x + 7 = 0 6x² - 2 x - 21x + 7 = 0 2 x(3 x – 1) – 7(3x – 1) = 0 (2 x – 7) (3 x – 1) = 0 x = 7/2 , 1/3 II. 6y² - 29y + 9 = 0 6y² - 27y - 2 y + 9 = 0 3 y(2 y – 9) – 1(2 y – 9) = 0 (3 y – 1) (2 y – 9) = 0 y = 9/2 , 1/3 Hence, x = y or the relationship cannot be established
I. 2y² - 35y + 132 = 0
II. 2x² - 31x + 110 = 0
I. x² - (16)2 = 0
II. 2y - 14 = 0
I. x2 – 18x + 81 = 0
II. y2 – 3y - 28 = 0
I. 81x - 117√x + 40 = 0
II. 81y - 225√y + 136 = 0
I. x2 – 12x + 32 = 0
II. y2 + y - 20 = 0
I. 2 x ² + x  – 1 = 0                Â
II. 2 y ² - 3 y + 1 = 0
...- What should be the value of t in the equation x² + tx + 64 = 0 so that it has two equal real roots?
How many values of x and y satisfy the equation 2x + 4y = 8 & 3x + 6y = 10.
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
l). p² - 26p + 153 = 0
ll). q² - 17q + 72 = 0
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