Question
I. 6x² - 23x + 7 = 0 II. 6y² - 29y + 9
= 0Solution
I. 6x² - 23x + 7 = 0 6x² - 2 x - 21x + 7 = 0 2 x(3 x – 1) – 7(3x – 1) = 0 (2 x – 7) (3 x – 1) = 0 x = 7/2 , 1/3 II. 6y² - 29y + 9 = 0 6y² - 27y - 2 y + 9 = 0 3 y(2 y – 9) – 1(2 y – 9) = 0 (3 y – 1) (2 y – 9) = 0 y = 9/2 , 1/3 Hence, x = y or the relationship cannot be established
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