Question

    If 3 sec² + tanθ – 7 = 0,0° <

    θ < 90°, then what is the value of (cosec2θ + cosθ)/(sin2θ + cotθ)?
    A (2 + √2)/4 Correct Answer Incorrect Answer
    B 5/2 Correct Answer Incorrect Answer
    C 10 Correct Answer Incorrect Answer
    D 4√2 Correct Answer Incorrect Answer

    Solution

    3 sec2 θ + tan θ = 7 ⇒ Put θ = 45 ⇒ 3 sec2 45 + tan 45 = 7 ⇒ 3 × 2 + 1 = 7 ⇒ 7 = 7 (satisfied) Now, ⇒ (cosec 2θ + cos θ)/(sin2θ + cot θ) ⇒ (cosec 90 + cos 45)/(sin 90 + cot 45) ⇒ (1 + 1/√2)/(1 + 1) ⇒ (√2 + 1)/2√2 ⇒ (2 + √2)/4

    Practice Next