Question
Pipe A can fill a tank in 12 hours. Pipes A and B
together can fill it in 6 hours. Pipes B and C together can fill it in 4 hours. In how many hours will pipes A, B and C together fill the tank?Solution
ATQ, A = 1/12 B = 1/6 − 1/12 B = (2 − 1)/12 = 1/12 B + C = 1/4 C = 1/4 − 1/12 C = (3 − 1)/12 = 2/12 = 1/6 A + B + C = 1/12 + 1/12 + 1/6 = (1 + 1 + 2)/12 = 4/12 Required time = 12/4 hours = 3 hours
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