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Let the efficiency of pipe 'Q' be '5a' litres/hour. So, efficiency of 'P' = 0.6 X 5a = '3a' litres/hour Total capacity of given tank = (3a + 5a) X 4 = '32a' litres Capacity of the tank to be filled by pipe 'Q' = 1.5 X 32a = '48a' litres New efficiency of pipe 'Q' = 0.8 X 5a = '4a' litres/hour Required time = (48a/4a) = 12 hours
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