📢 Too many exams? Don’t know which one suits you best? Book Your Free Expert 👉 call Now!

    Question

    Time taken by a tap to fill a tank is 8 hours. If the

    time taken by tap to fill the tank gets doubled due to a leakage in the tank, then find the time taken by 3 similar taps to fill the tank with 2 similar leakage in the tank.
    A 2 hours Correct Answer Incorrect Answer
    B 4 hours Correct Answer Incorrect Answer
    C 8 hours Correct Answer Incorrect Answer
    D 6 hours Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Time taken by tap to fill the tank with leakage = 8 × 2 = 16 hours
    So, time taken by leakage alone to empty the tank = 16/ (2 – 1) = 16 hours
    Time taken by 3 taps to fill the tank = (8/3) hours
    Time taken by 2 leaks to empty the tank = 16/2 = 8 hours
    Therefore, required time taken = [(8/3) × 8]/ [8 - (8/3)] = 64/16 = 4 hours

    Practice Next
    More Pipes and cisterns Questions

    Relevant for Exams:

    ask-question