Question
Time taken by a tap to fill a tank is 8 hours. If the
time taken by tap to fill the tank gets doubled due to a leakage in the tank, then find the time taken by 3 similar taps to fill the tank with 2 similar leakage in the tank.Solution
Time taken by tap to fill the tank with leakage = 8 × 2 = 16 hours
So, time taken by leakage alone to empty the tank = 16/ (2 – 1) = 16 hours
Time taken by 3 taps to fill the tank = (8/3) hours
Time taken by 2 leaks to empty the tank = 16/2 = 8 hours
Therefore, required time taken = [(8/3) × 8]/ [8 - (8/3)] = 64/16 = 4 hours
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