Pipe A alone fill the tank in x hours and Pipe B alone fill the tank in (x – 6) hours. If the efficiency of pipe B is double of pipe A and pipe A fill the tank is 50 liters per hour, then what is the capacity of the tank?
Pipe A alone fill 50 liters per hour, so Pipe B alone fill 100 liters per hour. Capacity of the tank = T => T/50 – T/100 = x – (x – 6) => 2T – T = 600 => T = 600 liters
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