Question
Pipe A can fill half of the tank in 6 hrs 2 min- Pipe B
can fill the same tank completely in 18 hrs 5 min while pipe C can empty the fully filled tank in 9 hrs, If all pipes are opened simultaneously then in how much time 80% of tank will be filled? (approximately)Solution
A can fill half of the tank in 6 hrs so, A can fill the full tank in 12 hrs B can fill the tank in 18 hrs C can empty the tank in 9 hrs Total capacity of tank = 36 unit (LCM of 12, 18 and 9) A can fill the tank in 1 hr = +3 B can fill the tank in 1 hr = +2 C can empty the tank in 1 hr = -4 Total tank filled in 1 hr = 3 + 2 – 4 = 1 unit  1% ≡ 36 unit 80% ≡ 36 × 80/100 = 29 units
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