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There are 4 possible cases 
The required number of ways = (4C3 × 4C3) + (3C1 × 4C2) × (4C2 × 3C1) + (3C2 × 4C1) × (4C1 × 3C2) + (3C3 × 3C3) = (4 × 4) + (3 × 6 × 6 × 3) + (3 × 4× 4 × 3) + (1 × 1) = 16 + 324 + 144 +1 = 485 ways.
Three of the four given words are alike in a certain way and thus form a group, which of the following words does not belong to the group?
Odd one out
Find the odd one out from the following options.
Three of the following four options are alike in a certain way based on the Alphabetical series. Which one among the following doesn’t belong to the g...
Select the letter cluster which does not belong to the same group from the given alternatives.
Four pairs of numbers have been given, out of which three are alike in some manner, while one is different. Choose out the odd one.
Find the odd one out
Four number-pairs are given, out of which three are alike in a certain manner and one is different. Choose the different number-pair.
Seven boxes J, K, L, M, N, O and P are kept one above another such that bottommost box is numbered as 1 and topmost box is numbered as 7. At least four ...
Odd one out
