In how many different ways can the letters of the word ‘PUBLIC’ be arranged in such a way that the vowels occupy only the odd positions?
There are 6 letters in the given word out of which there are 2 vowels and 4 consonants. Now, 2 vowels can be placed at any of the three places out of 3 odd positions. Number of ways of arranging the vowels =3P2= 3 Also, the 4 consonants can be arranged at the remaining 4 positions. Number of ways of arranging the consonants =4P4= 4! Total number of ways = (3 × 4!) = 72
If the sum of the squares of the roots of p2 - (x-2)p - (x+1) = 0 is 5 then what is the value of x.
A and B are the roots of equation x2 - 13x + k = 0. If A - B = 5, what is the value of k?
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