Question
A group consists of 12 boys and 7 girls. In how many
ways can 5 boys and 3 girls be selected from the group?Solution
Required number of ways = 12 C 5 × 7 C 3
= (12! / (5! × 7!)) × (7! / (3! × 4!))
= 792 × 35 = 27,720
231Â Â Â 451Â Â Â Â Â Â 671Â Â Â Â Â 242Â Â Â Â Â Â 485Â Â Â Â Â Â Â 264
...6000Â Â Â Â Â Â 3191Â Â Â Â Â Â 5216Â Â Â Â Â Â 3847Â Â Â Â Â Â 4688Â Â Â Â Â Â 4247
6125       a             b  �...
1 5 13 25 41 ?
2, A, 9, B, 6, C, 13, D, ?
2 3 3 ? 49 254
...6 3.5 2.5 ? 8.5 23.75
...217Â Â Â Â Â 267Â Â Â Â Â 304Â Â Â Â Â 330Â Â Â Â Â Â 348Â Â Â Â Â 357
...13 24 75 134 447 892
...16    9    11   26    ?    912
16 23 31 40 50 61 ?
...