Question
A group consists of 12 boys and 7 girls. In how many
ways can 5 boys and 3 girls be selected from the group?Solution
Required number of ways = 12 C 5 × 7 C 3
= (12! / (5! × 7!)) × (7! / (3! × 4!))
= 792 × 35 = 27,720
- If (p + q + r) = 10 and (pq + qr + rp) = 30, then find the value of (p² + q² + r²).
The value of:
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