Question
Two numbers are less than a third number by 40% and 46%
respectively. Find the percent by which the second number is less than the first.Solution
Let the third number be 100. Then, first number will be = 100 – 40 = 60 And the second number will be = 100 – 46 = 54 Required % = [(60 – 54)/60] × 100 = 10%
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