Question
A number exceeds 40 times its reciprocal by 7/8. Determine
the number.Solution
ATQ,
Let the number be x.
x – 40/x = 7/8
⇒ (x² – 40)/x = 7/8
Cross-multiplying:
8x² – 320 = 7x
⇒ 8x² – 7x – 320 = 0
Factorizing:
8x² – 40x + 33x – 320 = 0
8x(x – 5) + 64(x – 5) = 0
(8x + 64)(x – 5) = 0
So, x = –8 or x = 5
More No. System Questions
- Which letter and number cluster will replace the question mark (?) to complete the given series?
LT6, KU12, IW24, FZ48, ____ - A series is given with one term missing. Choose the correct alternatives from the given ones that will complete the series.
57, 59, 56, 61, 54, ___ - Which letter-cluster will replace the question mark (?) in the following series?
RGV, UME, ?, AYW, DEF - Select the number from among the given options that can replace the question mark (?) in the following series.
17, 18, 22, 31, 47, ___ - Which letter-cluster will replace the question mark (?) in the following series?
NPQR, OORQ, PNSP, ____, RLUN
Relevant for Exams:
