Question
The smallest number 'Q' which when divided by 12, 16, and
20 leaves 5 as the remainder in each case. Find the value of ('6Q' + 15).Solution
ATQ,
As we know the least number which is divisible by 'a', 'b', and 'c' is the LCM of 'a', 'b', and 'c'.
So, the number which is completely divisible by 12, 16, and 20 = LCM of
12, 16, and 20 = 240
So, 'Q' = 240 + 5 = 245
Now,
(6Q + 15) = (245 × 6) + 15 = 1470 + 15 = 1485
18, 32, 50, 82, 132, ?
5Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 6.5 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 20 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 113.5 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 799 Â ...
3, 49, 191, 477, ?, 1673
9 15 90 95 475 479
6 a b c d e
Find the value of c.
...1331      1000            729       512       ?             216
...Find the wrong number in the given series.
12, 18, 27, 42, 62, 87
18 113 559 2247 6721 13451
...6   16  ?     244  1,245  7,506  52,591
104Â Â Â Â Â Â 156Â Â Â Â Â Â Â 234Â Â Â Â Â Â Â ? Â Â Â Â Â Â Â 526.5Â Â Â Â Â Â Â 789.75
...3 2 2 3 8 ?
...
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