📱 Too many exams? Don’t know which one suits you best? Book Your Free Expert 👉 call Now!

    Question

    The smallest number 'Q' which when divided by 12, 16, and

    20 leaves 5 as the remainder in each case. Find the value of ('6Q' + 15).
    A 1485 Correct Answer Incorrect Answer
    B 1211 Correct Answer Incorrect Answer
    C 1375 Correct Answer Incorrect Answer
    D 1541 Correct Answer Incorrect Answer

    Solution

    ATQ,

    As we know the least number which is divisible by 'a', 'b', and 'c' is the LCM of 'a', 'b', and 'c'.

    So, the number which is completely divisible by 12, 16, and 20 = LCM of

    12, 16, and 20 = 240

    So, 'Q' = 240 + 5 = 245

    Now,

    (6Q + 15) = (245 × 6) + 15 = 1470 + 15 = 1485

    Practice Next
    More No. System Questions

    Relevant for Exams:

    ask-question