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ATQ,
A number divisible by 24 must be divisible by both 3 and 8.
Divisible by 3 → Sum of digits is divisible by 3
Divisible by 8 → Last three digits form a number divisible by 8
Option A: 8 + 2 + 5 + 1 + 9 + 6 = 31 → Not divisible by 3
Option B: 6 + 7 + 4 + 3 + 2 + 8 = 30 → Divisible by 3
Last 3 digits: 328 → 328 ÷ 8 = 41 → Divisible by 8 ✅
Option C: 5 + 9 + 2 + 4 + 1 + 6 = 27 → Divisible by 3
Last 3 digits: 416 → 416 ÷ 8 = 52 → Divisible by 8 ✅
Option D: 4 + 3 + 1 + 2 + 3 + 2 = 15 → Not divisible by 3
Hence, Both Option B and C are divisible by 3 and 8
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