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ATQ, Average score of KL Rahul = (78 + 34 + 56 + 90 + 45) ÷ 5 = 60.6 Average score of Rishabh Pant = (22 + 87 + 43 + 100 + 60) ÷ 5 = 62.4 So, the required difference = 62.4 – 60.6 = 1.8
120 × 195 ÷ 13 - ? = 162
33 × 5 - ?% of 250 = 62 - 6
60 % of 250 + √169 * 7 = ?² + 45 % of 160
25% of 400 + 3 × 102 = ?2
? = (22% of 25% of 60% of 3000) + 21
18/2 of 3/9 of 2/6 of 69690= ?
125% of 129 ÷ 43 × 28 ÷ 7 = ? ÷ √16