Question
The sum of the first 123 terms of the geometric
progression (GP) is equal to the sum of the first 121 terms of the Ursa geometric progression (GP). When the first term is 1235, what is the 99th term in the same quality series?Solution
S123= S121 a(r123-1)/r-1= a(r121-1)/r-1 r123 = r121 × 1 r2=1 r = ± 1 (all intervals) According to the question, r-1 First term = 1235 99th term of the series – T99 = a × r 99-1 = 1235 × 198 = 1235
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