Question
The sum of the first 123 terms of the geometric
progression (GP) is equal to the sum of the first 121 terms of the Ursa geometric progression (GP). When the first term is 1235, what is the 99th term in the same quality series?Solution
S123= S121 a(r123-1)/r-1= a(r121-1)/r-1 r123 = r121 × 1 r2=1 r = ± 1 (all intervals) According to the question, r-1 First term = 1235 99th term of the series – T99 = a × r 99-1 = 1235 × 198 = 1235
20% of 1500 – 75% of 200 = 125% of ?Â
24% of 150% of 500 + 140 = ? × 8Â
458.32 - 563.32 + 659.32 =?
What will come in the place of question mark (?) in the given expression?
(√1089 + 84 ÷ 2) % of 348 = 416 - ?
40% are the passing marks. A student gets 250 marks yet fails by 38 marks. What is the maximum marks?
(22.5 × 24) ÷ 40 + 51.50 = ? ÷ 5.25
36×?² + (25% of 208 +13) = 60% of 2400 + 17×18
What will come in the place of question mark (?) in the given expression?
√64 X 9 ÷ 3 + 12 X 3 = ? + 36(3/7) x 868 + 25% of 240 = (? + 65)
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