Question
Mixture 'A' contains 20% water and rest milk which is equal to 60% of quantity of water in mixture 'B' (milk + water). Ratio of quantity of milk in mixture 'A' and mixture 'B' is 2:3, respectively. If difference between total quantity of mixture 'A' and mixture 'B' is 184 litres, then find the difference between quantities of water in given two mixtures.
Solution
Let quantity of water in mixture 'B' be '5x' litres Quantity of milk in mixture 'A' = 0.6 × 5x = '3x' litres Total quantity of mixture 'A' = (3x/0.8) = 3.75x litres Quantity of water in mixture 'A' = (3.75x − 3x) = 0.75x litres Quantity of milk in mixture 'B' = (3x × 3/2) = 4.5x litres Total quantity of mixture 'B' = (5x + 4.5x) = 9.5x According to the question, (9.5x − 3.75x = 184) Or, (5.75x = 184) Or, x = 32 Required difference = 5x − 0.75x = 4.25x = 4.25 × 32 = 136 litres
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