Question
150 litres of mixture contains water and milk in the
ratio 3:5 respectively. If 54 litres of the mixture is replaced by same quantity of water, then find the ratio of water and milk in the final mixture.Solution
Remaining quantity of the original mixture = 150 – 54 = 96 litres Quantity of water in the final mixture = 96 x (3/8) + 54 = 90 litres Quantity of milk in the final mixture = 66 x (5/8) = 60 litres Ratio of water and milk in the final mixture = 90 : 60 = 3:2
`(sqrt(960.87)xx9.932+sqrt(629.998)xx26.385)/(sqrt(1028.902)xx4.977)=?`
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
99.99% of 9.99 + 299.98% of 129.98 = ?2Â
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
(29.98% of 9840) + ? + (19.899% of 8490) = 7560
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
4650.12 ÷ √8648.88 + √27.08 * √1727.85 = ? – 609.10 ÷ 87.07                     Â
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