Question
In a mixture of 12 liters containing vinegar and Soya
sauce, the vinegar constitutes 25% of the mixture. After removing 4 liters of this mixture, 10 liters of another mixture with 20% vinegar is added. Determine the ratio of vinegar to soya sauce in the final mixture.Solution
ATQ, In the first mixture, Vinegar:Soya sauce = 25:75 = 1:3 Quantity of Vinegar in 12 litres of the mixture = 12 Γ 1/4 = 3 litres Quantity of Soya sauce in 12 litres of the mixture = 12 β 3 = 9 litres When 4 litres of mixture is pour out then, Quantity of Vinegar taken out = 4 Γ 1/4 = 1 litre Quantity of Soya sauce taken out = 4 β 1 = 3 litres In the second mixture, Vinegar:Soya sauce = 20:80 = 1:4 Quantity of Vinegar in 10 litres of the mixture = 10 Γ 1/5 = 2 litres Quantity of Soya sauce in 10 litres of the mixture = 10 β 2 = 8 litres Quantity of Vinegar in the final mixture = 3 β 1 + 2 = 4 litres Quantity of Soya sauce in the final mixture = 9 β 3 + 8 = 14 litres Required ratio = 4:14 = 2:7
(22Β Γ 52 ) + 4 Γ 6 = ? - β324
What should come in place of (?) question mark in the given expression.
Β (25% of 320) + (3/8 of 400) β 30 = ?
(5832)1/3 Β Γ 10.11 Γ 11.97 Γ· 16.32 = ?Β + 45.022
82% of 400 + √(?) = 130% of 600 - 85% of 400
If (x + 1/x) = 5, then value of x3 + 1/x3 is:
Simplify: (1 Γ· 0.08)
What should come in place of (?) question mark in the given expression.
{ (144 Γ· 12) Γ 5 } β (18 Γ· 3) = ?
Simplify the following expressions and choose the correct option.
(3/4 of 256) + (2/5 of 150) - (72 Γ· 7)
464 + 181 +? = (154 Γ 25) - (15) 2 Β
15% of 1800 + 22 = ?Β