Question
55% of the original 'a' liters of pure petrol is taken
out from a container and replaced with 66 liters of Methanol, ensuring the total quantity of the mixture remains constant. Determine the ratio of petrol to Methanol in the resulting mixture 'M,' which initially contains (0.75a + 10) liters of petrol and '2a' liters of Methanol.Solution
ATQ, Total quantity of mixture = a = 66/0.55 = 120 litres Therefore, quantity of petrol in mixture βMβ = (0.75a + 10) = 0.75 Γ 120 + 10 = 90 + 10 = 100 litres Quantity of Methanol in mixture βMβ = 2a = 240 litres Required ratio = 100:240 = 5:12
(22Β Γ 52 ) + 4 Γ 6 = ? - β324
What should come in place of (?) question mark in the given expression.
Β (25% of 320) + (3/8 of 400) β 30 = ?
(5832)1/3 Β Γ 10.11 Γ 11.97 Γ· 16.32 = ?Β + 45.022
82% of 400 + √(?) = 130% of 600 - 85% of 400
If (x + 1/x) = 5, then value of x3 + 1/x3 is:
Simplify: (1 Γ· 0.08)
What should come in place of (?) question mark in the given expression.
{ (144 Γ· 12) Γ 5 } β (18 Γ· 3) = ?
Simplify the following expressions and choose the correct option.
(3/4 of 256) + (2/5 of 150) - (72 Γ· 7)
464 + 181 +? = (154 Γ 25) - (15) 2 Β
15% of 1800 + 22 = ?Β