Mixture 'A' contains 25% water and rest milk which is equal to 50% of quantity of water in mixture 'B' (milk + water). Ratio of quantity of milk in mixture 'A' and mixture 'B' is 3:4, respectively. If difference between total quantity of mixture 'A' and mixture 'B' is 120 litres, then find the difference between quantities of water in given two mixtures.

Let quantity of water in mixture 'B' be '4x' litres Quantity of milk in mixture 'A' = 0.5 × 4x = '2x' litres Total quantity of mixture 'A' = (2x/0.75) = (8x/3) litres Quantity of water in mixture 'A' = (8x/3 − 2x) = (2x/3) litres Quantity of milk in mixture 'B' = (2x × 4/3) = (8x/3) litres Total quantity of mixture 'B' = (4x + 8x/3) = (20x/3) litres According to the question, ((20x/3) − (8x/3) = 120) Or, (12x/3 = 120) Or, (4x = 120) Or, x = 30 Required difference= (4x − 2x/3) = 12x/3 − 2x/3 = 10x/3 = 10 × 30/3 = 100 litres