📢 Too many exams? Don’t know which one suits you best? Book Your Free Expert 👉 call Now!

    Question

    Mixture 'A' contains 25% water and rest milk which is

    equal to 50% of quantity of water in mixture 'B' (milk + water). Ratio of quantity of milk in mixture 'A' and mixture 'B' is 3:4, respectively. If difference between total quantity of mixture 'A' and mixture 'B' is 120 litres, then find the difference between quantities of water in given two mixtures.
    A 60 litres Correct Answer Incorrect Answer
    B 80 litres Correct Answer Incorrect Answer
    C 100 litres Correct Answer Incorrect Answer
    D 120 litres Correct Answer Incorrect Answer
    E 90 litres Correct Answer Incorrect Answer

    Solution

    Let quantity of water in mixture 'B' be '4x' litres Quantity of milk in mixture 'A' = 0.5 × 4x = '2x' litres Total quantity of mixture 'A' = (2x/0.75) = (8x/3) litres Quantity of water in mixture 'A' = (8x/3 − 2x) = (2x/3) litres Quantity of milk in mixture 'B' = (2x × 4/3) = (8x/3) litres Total quantity of mixture 'B' = (4x + 8x/3) = (20x/3) litres According to the question, ((20x/3) − (8x/3) = 120) Or, (12x/3 = 120) Or, (4x = 120) Or, x = 30 Required difference= (4x − 2x/3) = 12x/3 − 2x/3 = 10x/3 = 10 × 30/3 = 100 litres

    Practice Next
    More Mixture Questions

    Relevant for Exams:

    ask-question