Question
60 grams of an alloy 'A' containing only gold, silver and
copper in ratio 3:2:5 respectively is mixed with 20 grams of alloy 'B' which contains only silver and copper in ratio 3:1 respectively. Find the total ratio of silver to copper in the final mixture.Solution
Quantity of silver in 60 gram of alloy 'A' = 60 × (2/10) = 12 gram
Quantity of copper in 60 gram of alloy 'A' = 60 × (5/10) = 30 gram
Quantity of silver in 20 gram of alloy 'B' = 20 × (3/4) = 15 gram
Quantity of copper in 20 gram of alloy 'B' = 20 × (1/4) = 5 gram
Required ratio = (12 + 15) : (30 + 5) = 27 : 35
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