Question
A mixture contains salt and water
in the ratio of 2:5 respectively. If the ratio of the cost of salt and that of the mixture of salt and water is 9:4, then find the ratio of the cost of salt to that of water.Solution
ATQ, Let the cost of salt, cost of mixture, and cost of water be 9x, 4x, and y respectively. CP of Salt       CP of Water 9x                y        4x (4x − y)            5x (4x − y)/5x = 2/5 20x − 5y = 10x 10x = 5y = x/y = 1/2 Ratio of cost of salt to that of water = 9x:y = 9(1):2 = 9:2
Age of ‘A’ after 8 years will be three time of his age 20 years ago. Eight years hence from now, ratio of ages of ‘A’ and ‘B’ will be 2:3, r...
Reena is twice as old as Sunita .Three years ago, she was three times as old as Sunita. How old is Reena now?
Present age of ‘A’ is 40% more than that of ‘B’. If 11 years hence from now, ‘B’ will be 10 years younger than ‘A’, then find the sum of...
The ratio between the present age of Beena and Meenal is 5:7, where Sumit is 6 years younger than Meenal then find the ratio of their ages 9 years hence.
After 5 years, the age of Seema will be 3 years less than 3 times of her age, 4 years back. What is Seema’s present age?
Present average age of 4 friends: ‘A’, ‘B’, ‘C’ and ‘D’ is 33 years. If their ages are in the arithmetic progression in the same order a...
Five years ago from now, age of 'A' was ____ years. Ratio of present ages of 'A' and 'B' is ____ respectively and three years hence from now, sum of ag...
A is 3 years older than B while C is 5 years younger than B. The ratio of age of A, 6 years hence and age of B, 3 years ago is 4:3. What was age of C, 1...
7 years ago, the ratio of the ages of A and B was 1:2 and after 7 years it will become 3:5. Find their present ages.
6 years ago, the ratio of the ages of A and B was 2:3 and after 7 years it will become 3:4. Find their present ages.
