Question
150 litres of a mixture contains 30% milk and rest
water. If ‘x’ litres of milk is added into the mixture then quantity of water in the final mixture becomes 30% of total quantity of mixture. Find the value of ‘x’.Solution
Quantity of milk in the initial mixture = 150 × 0.30 = 45 litres Quantity of water in the initial mixture = 150 – 45 = 105 litres Quantity of water is unchanged in the final mixture. So, Quantity of final mixture = (105/30) × 100 = 350 litres Quantity of milk in final mixture = 350 – 105 = 245 litres Value of ‘x’ = 245 – 45 = 200
95.001% of 8219.99 - 4/9 % of 5399.98 + 109.99 = ?
25.05% of 220.05 – 10.15% of 119.99 × 2.02 = ?
16.98 × 88.05 + 1999.996% of 299.08 + 5.005 % of 4999.997 = ? × 20.98 × 40.009
(32.18% of 2399.89 - √624 × 26.25) % of 149.79 = ?
(752.09 - 43.04 x 7.94) ÷ 16.9 = ?
(44/25) ÷ (154/199.5) × 419.91 = ? – (11.11)3
39.99% of 159.98 = ?2 – 319.99% of 12.5 – 49.98% of 129.99
15.22 × 9.99 + 150.15 = ?
Raju invests Rs. (p + 200) at a simple interest rate of 25% per annum for a period of 6 years and earns a total interest of Rs. (...
2660.03 ÷ 69.98 x 49.9 = ? + 10.32
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