Question
Two alloys named 'X' and 'Y' contain gold and silver in
the ratio of 3:2 and 7:5 respectively. If 100 grams of X and 120 grams of Y are mixed together, then find the ratio of gold to silver in the final mixture.Solution
Quantity of gold in 100 grams 'X' = 100 × (3/5) = 60 grams
Quantity of silver in 100 grams 'X' = 100 - 60 = 40 grams
Quantity of gold in 120 grams 'Y' = 120 × (7/12) = 70 grams
Quantity of silver in 120 grams 'Y' = 120 - 70 = 50 grams
So, required ratio = (60 + 70) : (40 + 50) = 130 : 90 = 13:9
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