Question
Mixture 'A' contains 20% water and rest milk which is
equal to 40% of quantity of water in mixture 'B' (milk + water). Ratio of quantity of milk in mixture 'A' and mixture 'B' is 2:5, respectively. If difference between total quantity of mixture 'A' and mixture 'B' is 150 litres, then find the difference between quantities of water in given two mixtures.Solution
Let quantity of water in mixture 'B' be '5x' litres Quantity of milk in mixture 'A' = 0.4 × 5x = '2x' litres Total quantity of mixture 'A' = (2x/0.8) = '2.5x' litres Quantity of water in mixture 'A' = 2.5x − 2x = '0.5x' litres Quantity of milk in mixture 'B' = 2x × (5/2) = '5x' litres Total quantity of mixture 'B' = 5x + 5x = '10x' litres According to the question, 10x − 2.5x = 150 Or, 7.5x = 150 Or, 'x' = (150/7.5) = 20 Required difference = 5x − 0.5x
= 4.5x
= 4.5 × 20
= 90 litres
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