Question
270 litres of mixture 'X' contains milk and honey, only in
the ratio 7:2, respectively and 480 litres of mixture 'Y' contains milk and honey, only in the ratio 13:3, respectively. If mixtures 'X' and 'Y' are mixed, then what will be ratio of quantities of milk to that of honey in the resultant mixture?Solution
ATQ,
Quantity of milk in mixture 'A' = 270 X (7/9) = 210 litres
Quantity of honey in mixture 'A' = 270 - 210 = 60 litres
Quantity of milk in mixture 'B' = 480 X (13/16) = 390 litres
Quantity of honey in mixture 'B' = 480 - 390 = 90 litres
Therefore, required ratio = (210 + 390) :(60 + 90) = 600:150 = 4:1
What value should come in place of the question mark (?) in the following question?
(1/3) + (2/5) + (3/4) + (11/10) = 3 �...
√(?) ² = √7396 - √6889
[(11)2 - (12)2 + (5)3]2 = ?
Find the value of 27 ÷ 2 of 16 of [6 ÷ 8 of (6 ÷ 2 + 5)] + (10 ÷ 2.5 + 1)
((1024)n/5 × (42n+1 ))/(16n × 4n-1 ) = ?
What is the value of 143 + 163 + 183 + … + 303?
(20% of 15% of 600 – 6) × 5 + 84 = ?2
63 × 4 = ?2 – 1620 ÷ 5
65% of 102 + 14 = ? – 20
What will come in the place of question mark (?) in the given expression?
216 ÷ 6 + √? - 126 ÷ 7 = 23 X 2