Question
Quantity of water in a 280 litres mixture (alcohol +
water) is 40 litres less than the quantity of alcohol in it. Find the quantity of water to be mixed so that the quantity of alcohol in the mixture becomes 50% of the whole mixture.Solution
Quantity of water in the mixture = (280 β 40)/2 = 120 litres So, Quantity of alcohol in the mixture = (280 β 120) = 160 litres Total quantity of the mixture = 160 x (100/50) = 320 litres Therefore, quantity of water to be mixed = 320 β 280 = 40 litres
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