Question
A vessel has 20L of 25% acid solution. How much pure
acid must be added to make it 40% acid?Solution
ATQ,
25% → pure acid = 5L. Let x = pure acid added → (5+x)/(20+x)=0.4 → 5 + x = 8+0.4x → 0.6x = 3 → x = 5L.
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