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      Question

      A container has 60 ml of a mixture of milk and water in the

      ratio 4 : 1. Then 20% of the mixture is removed and the same quantity is replaced with pure milk. As a result, the final ratio of milk to water becomes 5 : 1. What is the quantity of milk added (in ml)?
      A 6 ml Correct Answer Incorrect Answer
      B 10 ml Correct Answer Incorrect Answer
      C 2.5 ml Correct Answer Incorrect Answer
      D 8.4 ml Correct Answer Incorrect Answer
      E None of these Correct Answer Incorrect Answer

      Solution

      ATQ, Initial milk = 60 × 4/5 = 48 ml Initial water = 60 × 1/5 = 12 ml 20% of 60 ml = 12 ml mixture removed (still in 4:1): Milk removed = 12 × 4/5 = 48/5 = 9.6 ml Water removed = 12 × 1/5 = 12/5 = 2.4 ml Milk left = 48 − 9.6 = 38.4 ml Water left = 12 − 2.4 = 9.6 ml Let x ml milk added. Final ratio = 5 : 1: (38.4 + x) / 9.6 = 5 38.4 + x = 48 x = 9.6 ml

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